Initiation / Pyramid Architecture

[3D Sunset]

I sure wish Don was still around to comment in these threads. What a resource that would be! Then again, everyone loves a good puzzle, myself included.

Hi Lavazza,

For what it's worth, as I was looking over your projection/rotation figures, it occurred to be that if you start with your 2D representation of the 4 triangles, then anchor that at the top, rather than the bottom of the pyramid, then the resulting diamond formed where the bottom of the 2D representation intersects the four faces, is at about the right height for the Queen's chamber.

I don't have the tools handy to draw it, but looking at the difference between where the tip of your 2D rotation comes to rest on the side of the pyramid is about 1/6th the way from the actual top of the pyramid.

This comes close to meeting Ra's description if you then interpret "intersection of the triangle which is at the first level" means the bottom level of the 4 triangle representation (granted, this would more correctly be called the "intersection of the triangles"). I'm not sure if this will take us anywhere, but rereading the discussion about "projections" in s/t and t/s just brought me back to your earlier diagram.

Am I describing my idea clearly enough for you to try it?

3D Sunset