Initiation / Pyramid Architecture

[Willis]

Alright guys, I went on a binge because this was really cool to check out, and found some interesting conclusions.

I decided to push this perpendicular tunnel idea further, to see if it would lead me to an answer for the 1/6 calculation. I turned it into a line, ending in a sphere set in the center of the pyramid, representing the queen's chamber. I also connected the chamber to two points, one along the corner edge, and a central line going up the face. Both are at the same height as the queen's chamber.

Once those were in place and I got the measurements, I did a few equations:

1/6 = 0.166666
116.978/611.76 = 0.1915
137.507/719.117 = 0.1912
116.978/719.117 = 0.1627

The closest one to 1/6 was the ratio between the portion of the central line and the length of the corner edge, highlighted in yellow in the pic below.



It's still a little fuzzy to me, but perhaps this might have been the train of thought Don was on when this was discussed with Ra. Perhaps Don made an approximation of 1/6, and we all know how much Ra loves approximations when it comes to numbers